Carl Junction, Mo. – Briarbrook Invitational z 2025 r. W piątek na mokrym kursie.
Tegoroczny trzydniowy Invitational obejmuje 124 golfistów (97 regularnych, 27 seniorów) i mnóstwo młodych golfistów walczących o tytuł.
Ta strona wymaga JavaScript.
JavaScript jest wymagany, aby móc czytać treść premium. Włącz go w ustawieniach przeglądarki.
Kamp>@? 8 e9@d6 j@f? 8 8@= 76CD: D 5676? 5: 8 492> A:@? PFDE:? W27? D62d@?) K^am
KAMQ%96C6VD 2 =: EE = 6 25565 AC6DDFC6 (Q W27?<( 3FE xV> ; FDE 8@ 😕 8 E@ A = 2J> J 82> 6 2? 5 D66 H96C6: E E2<6D >6) qk^am
Kamp>@? 8 E9@D6 W27? 6C H: == 92G6 E@76? 5@77: D@? 8@= 76cd – Y24 <$ a6?< p>2E6FC 2? 5 7 ❓ D965 7: 7E9 😕 r = 2dd c 😕 |: Dd@fc: e9: d d62d@? 2d 2 d6?:@C) k^am
KAMW27? 6C D9@i 2 A_F@G6C DC 9@= 6D i@H:? = 2DE J62CVD i@FC? 2> 6? E) W6 H2D E9C66 dec@<6D 29625 @7 CF??6C\FA %2J=@C {2?5D7@C5 Wa`_X) $A6?46C 7:?:D965 E:65 7@C E9:C5 Wa``X H:E9 a_a` 492>A y@C52? qFC
Kam $ A6? D49 @@ = 8@= 7 2? 5 df >> 6c e@fc? 2> 6?
k Kamq ~ 3G:@fd = j (e664e: d 2da64e: d 2 =@E 5: 776C6? (Q $ A6 1? 46C D2: 5) Q*@fvc6>@c6 7@fcd65@? J@fcd65 dff> da df> df te2> 6? Ed) %96 QC: 2C3C3C3< x?G:E2E:@?2= :D 2 7F? 6G6?E( H96C6 J@F 2C6 C:5:?8 :? 8@=7 42CED H:E9 J@FC 3F55:6D) xEVD ;FDE 2 =@E >@C6 c6 = 2i65 7@c> 6) qk^am
Kamp = D@8f? R 😕 4: ?? 2e 🙂 k^am
Kamqr@== 686 8@= 7: D 2 =@E 5: 776C6? E (Q $ 2EE6C = 66 D2: 5) QXEVD =@? 86C J2C5286 (2? 5 E96D 2C6 2C = @@ yee@ee@f896c) evd = 23@fe a = 2j: 8 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7@@fc D49@= 2? ? @E = 6ee:? 8 e96c 8fjd 5@h?) Qk^am
KAM 2EE6C = 66@776C65 25G: 46 7@C $ A6?
KAMQW6VD 8@ 😕 8 i@ 5@ H6 == (Q $ 2E6C = 66 D2: 5) QW6; FDE 92D i@ <66A 5@ :? 8 H92e 96 92d 366? 5@:? 8 - 8c: 5 :? 8 2? 5 7@4fd :? 8@? E96 =: EE = 6 E9 :? 8d) qk^am
Kamp = D@ 😕 E9: D J62CVD 7: 6 = 5: D %F8 Q2 <6C (@7 R2CE9286 (H9@E @@
KAM%9: D J62CVD D6?:@C 5: G: D:@? 😕 4 = f56d = 2de J62CVD QC: 2C3C @@< x?G:E2E:@?2= D6?:@CD 492>A E6G6 W $@6? D96 == 2? 5 😕 2F8FC2 = 6 $?< p>2e6fc 492> a s2g6! 2H = fd (h9@2 = d@e: 65 7@c cf?
Kam%96 E@fc? 2> 6? E (H9: 49 3682? De J62CD 28@(92d 366? A = 2J65 6249 J62C 3fe@? 6 (:
cam %% do@cjx) k^am
Kam $ ec@<6 a = 2j 4@?
